Wednesday, March 02, 2011

MAC Reset....and permutations


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RankWLPctGames RemainingHome GamesWho do they play
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1Kent State1140.73311AK
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2Miami (OH)1040.71421@Buffalo, OU
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3BSU950.64321@WMU, NIU
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WMU950.64321Ball, @CMU
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5Akron960.60010@Kent
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Ohio960.60010@MIami
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7Buffalo770.50021Miami, @BG
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8Bowling Green780.46711Buffalo
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CMU780.46711WMU
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10EMU4100.28621@NIU, UT
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11NIU4100.28621EMU, @Ball
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12UT1140.06710@EMU


Here are the updated possibilities, based on my best reading of the MAC tie-breaker procedures. I have updated these from earlier in the week. The permutations are updated based on tonight's results, most notably the OU win, CMU win and BG loss.

If BG wins both they go 9-7, they have home court

If BG goes 8-8: (There are a number of ways that could happen).

Four way tie, BG, OU, Buffalo, CMU BG w/BG win over Buffalo

The tie breaker is the record among the four years, using winning percentage.

Among these four teams:

BG 3-2
Buffalo 2-3
OU 2-3
CMU 2-1

Therefore

6. CMU
7. BGSU

Four way tie, BG, OU, Buffalo, CMU BG w/Buffalo win over BG


Among these four teams:


BG 2-3
Buff 3-2
OU 2-3
CMU 2-1

6. CMU
7. Buffalo
8. BG (Depends on whether Miami or Kent finishes first, but probable due to BG's Miami win).
9. OU


3-way tie, Buffalo, BG, CMU w/BG win over Buffalo


Among these three teams:


BG 2-1
Buffalo 1-2
CMU 1-1

7. BG
8. CMU
9 Buffalo

3-way tie, Buffalo, BG, CMU w/Buffalo win over BG

BG 1-2
Buffalo 2-1
CMU 1-1

7. Buffalo
8. CMU
9. BG


2-way tie with BG and CMU, with Buffalo at 7-9

7.  CMU
8.  BGSU
9.  Buffalo

BG loses out and finishes 7-9

If CMU loses both...

8. BG
9. CMU


If CMU loses one or none

8. CMU
9. BG

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