MAC Reset....and permutations
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Here are the updated possibilities, based on my best reading of the MAC tie-breaker procedures. I have updated these from earlier in the week. The permutations are updated based on tonight's results, most notably the OU win, CMU win and BG loss.
If BG goes 8-8: (There are a number of ways that could happen).
The tie breaker is the record among the four years, using winning percentage.
Among these four teams:
BG 3-2
Buffalo 2-3
OU 2-3
CMU 2-1
Therefore
6. CMU
7. BGSU
Four way tie, BG, OU, Buffalo, CMU BG w/Buffalo win over BG
Among these four teams:
BG 2-3
Buff 3-2
OU 2-3
CMU 2-1
6. CMU
7. Buffalo
8. BG (Depends on whether Miami or Kent finishes first, but probable due to BG's Miami win).
9. OU
3-way tie, Buffalo, BG, CMU w/BG win over Buffalo
Among these three teams:
BG 2-1
Buffalo 1-2
CMU 1-1
7. BG
8. CMU
9 Buffalo
BG 1-2
Buffalo 2-1
CMU 1-1
7. Buffalo
8. CMU
9. BG
2-way tie with BG and CMU, with Buffalo at 7-9
7. CMU
8. BGSU
9. Buffalo
BG loses out and finishes 7-9
8. BG
9. CMU
If CMU loses one or none
8. CMU
9. BG
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